Bodybuilding Articles

Determining Natural Bodybuilding Potential

  • 128

Can you determine natural bodybuilding potential? Is it possible to determine if a lifter is a natural or steroid user? The answer is generally yes to both questions.

The formula. The following equation is derived scientifically, studying approximately 300 winning drug-free strength training athletes and bodybuilders from 1947-2007. For more information please read this article, Your Maximum Muscular Bodyweight and Measurements.

H = Height in inches

W = Wrist circumference located at the hand side of the bony lump on the wrist (known as the styloid process)

A = Ankle circumference at the smallest measurement

BF% = The bodyfat percentage at which the ankle and wrist circumferences were taken

natural muscle potential

Potential Variance. The natural bodyweight potentials listed below are derived using a wrist circumference of 7.5 inches, and an ankle circumference of 9.5 inches. These numbers are reasonable for the heaviest of natural lifters. (Note: the author’s wrist circumference is 8.0 inches, and ankle circumference is 10.0 inches at a bodyweight of 280 pounds. So you can see that for a natural lifter under 220 pounds, 7.5 and 9.5 are very reasonable numbers)

For a 0.5 differential in BOTH numbers (a lifter’s wrist is 8.0 inches and ankle is 10.0 inches instead of 7.5 and 9.5), the weight variance using the formula would be an additional 5.2 pounds of lean mass. In simple terms, for every additional inch of circumference (from either ankle, wrist, or both combined) above the potentials listed below, a lifter could have an additional 5.2 pounds of lean mass.

Again, keep in mind that the numbers used to derive natural potential (7.5 wrist circumference and 9.5 ankle circumference) are at the high end of normal for a natural bodybuilder with under 20% bodyfat. Therefore, a reasonable maximum potential variance for natural lifters from the below numbers would be plus 3 pounds. For smaller wrist/ankle boned lifters, the numbers could be smaller by up to 10 pounds.

The numbers. Using the above formula, and inserting 7.5 wrist inches and 9.5 ankle inches, we derive the following natural bodyweight lean body mass potentials for a 6% bodyfat percentage. Again, the derived numbers below are lean bodyweight, which means total bodyweight less fat. It is not total competition bodyweight including the 6% bodyfat.

The reduced formula with wrist and ankle circumferences and a 6% bodyfat percentage is…

H^1.5 (0.31037632)

Height, 66 inches = 166.4 lean body mass potential. Competition weight = 177.0 pounds

Height, 67 inches = 170.2 lean body mass potential. Competition weight = 181.1 pounds

Height, 68 inches = 174.0 lean body mass potential. Competition weight = 185.1 pounds

Height, 69 inches = 177.9 lean body mass potential. Competition weight = 189.3 pounds

Height, 70 inches = 181.8 lean body mass potential. Competition weight = 193.4 pounds

Height, 71 inches = 185.7 lean body mass potential. Competition weight = 197.6 pounds

Height, 72 inches = 189.6 lean body mass potential. Competition weight = 201.7 pounds

Height, 73 inches = 193.6 lean body mass potential. Competition weight = 206.0 pounds

Height, 74 inches = 197.6 lean body mass potential. Competition weight = 210.2 pounds

Height, 75 inches = 201.6 lean body mass potential. Competition weight = 214.5 pounds

Height, 76 inches = 205.6 lean body mass potential. Competition weight = 218.7 pounds

Bottom line. It is possible for a natural lifter to exceed these numbers by a very small percentage. But, it is virtually impossible for a natural lifter to exceed their potential by more then a few pounds. Based on ankle and wrist circumference, I think it is safe to say that a lifter who exceeds their natural potential by more than 5-10 pounds lean mass is certainly suspect.

Steve Shaw

Steve Shaw is the primary content manager for Muscle and Brawn.

Latest posts by Steve Shaw (see all)

  • alan Dec 9,2014 at 5:04 pm

    Completely disagree. I’m 6 ft 1 210lb about 10% body fat. 28 yrs old and nowhere near my potential. I’m naturally thin but I know I could get to 235lb at 6%bf with dedication and naturally and I will do it. 8 years ago I was as skinny as a rake at 140 lb. Back then I eat crap and smoked week. I am living proof a very skinny lanky guy can get big and strong naturally. It just takes years of working out. One thing I will say is, when I was skinny, I would have swapped my body with a 5 ft 9 normal body in a second. I hated my body. I used to double up on clothes just to look bigger. Now as a pretty big guy (not massive) I love my body and a lot of blokes would love to have a body like mine. If you want something hard enough, you can have it if you just stick with it! I love being strong I love it!!

    • Mick Madden Dec 12,2014 at 1:48 pm

      Go ahead and disagree. You’ll never get there naturally. If you do you’ll be the greatest natural of all time AND defy human physiological limits.

      • Alan Dec 13,2014 at 6:52 am

        hahahahah OK mary!! Get that nolva down you

  • Mike May 15,2014 at 10:07 am

    I know this is an old article, but I have just one quick question and may have missed it somewhere.
    For BF% I’m heavy at 29.5% So should I use 29.5 in the formula or 0.295? One gives me 183 as max lean mass and the other gives me 162. I’m 66″ tall with a 7″ wrist and 10″ ankle. My current lean mass is 161, so I’d assume that I should be using the larger number. Just wanting some confirmation.

  • DJT May 12,2013 at 4:31 pm

    When it comes to the human body and nature, nothing is predictable, and nothing can ever fit perfectly into a formula or equation. In math, numbers are always numbers and they work out precisely every time, as long as you know what you are doing. For the past thirteen years I have been a natural bodybuilder and my weight gets up to 228 lbs. at 5’11”. Around ten to thirteen percent BF. When I grow I can always see my top four abs clearly. When I shred I usually get down to 212-216 lbs. with my lower abs, obliques, intercostals and serratus clearly defined. I haven’t measured my wrists or ankles but they appear very thin compared to my calves and forearms. Don’t give a shit about non-believers cause I’m looking sexy as shit, according to my plethora of sexy fitness women hanging on my arm. Formulas are for fools, the human body is more unique and complex than numbers.

    • Mick Madden May 13,2013 at 11:52 pm

      Bullcrap. Post a picture in the forum. I guarantee your body fat percentage is way off. “Nothing is predictable” = faery tale. Keep believing you can overcome human physiology 101 if you only try hard enough. These formulas are based on natural champions, and you have the balls to state you are the best ever. Post a pic.

  • Jani Mar 8,2013 at 7:08 am

    Something is wrong with the equation. My wrist=6,7″, ankle 9,45″ and my height 70″
    When I try to do the math as presented above, I get 34,30 as a result =)
    And no, I’m not an idiot, but let me still present this once:
    Height x 1,5 = 105
    Wrist cf squared and then divided by the weird number given above (22,6670) = 0,1141
    Ankle cf squared and then divided by the other weird number above (17,0104) = 0,1807
    The last two added together = 0,2948
    Body fat % 24,3 divided by 224, after which 1,0 is added = 1,1084
    So 105 x 0,2948 x 1,1084 = 34,3094
    Apparently the weird numbers didn’t belong there. I just don’t know what does =)

    • Carlos Apr 19,2014 at 12:13 pm

      Dude it’s not height x 1.5 it’s height to the power of 1.5. Example – 10x 1.5 = 15. 10^1.5 = 31.6

  • Jeff Oct 24,2012 at 9:11 pm

    So, I’m currently 225 lbs, 20% bf, wrist = 7.25″ and ankle is 9.5″, height 70″…if I calculated correctly, I should max at around ~193 lbs of LBM…and at my weight and BF% I’m at ~180 lbs of LBM….which means I have a while before I max out…and I have a lot of growing to go…sweet…

  • RB Apr 2,2012 at 3:21 pm

    Anything is possible, I have already passed my LBM potentional 12+ pounds and havent even been lifting for 1.5 years. Wouldnt even know how to use steroids either. The human body is capable of amazing things.

    • Mick Madden Apr 2,2012 at 4:16 pm

      Don’t believe it. That would make you much larger than the best current pro naturals, because none of them have surpassed these numbers. You math is off.

      Post pics here so we can see:

  • Calling out fawker Jun 28,2011 at 4:02 pm

    […] the subject. No natural champion has ever beat these predictions by more than a trivial amount. Determining Natural Bodybuilding Potential – Muscle and Brawn Bodybuilding, Powerlifting and Muscle … H^1.5 (0.31037632) The below numbers are at 6% bodyfat. Height, 66 inches = 166.4 lean body mass […]

  • […] ass than I thought. Making the jump from Layne to Skip is really idiotic. Here, homework 101: Determining Natural Bodybuilding Potential – Muscle and Brawn Bodybuilding, Powerlifting and Muscle … Layne falls within his projected natural potential limits, where Skip is well beyond his projected […]

  • jimmy Feb 20,2011 at 8:50 am

    This is pretty sweet.

  • jimmy Dec 7,2009 at 7:00 am

    hey…..This is one of the best blog for Nature body building.You given maths wise description its good for easy learn.thanks …..

  • […] 2 Huge – Math for BBing Determining Natural Bodybuilding Potential | Muscle and Brawn. __________________ I am da ALL The Misc Mon-kay #1 (the only one)! OFFICIAL MISC: Hawk Fan #84 […]

  • […] article on natural bodybuilding potential is based on Casey Butt’s study. The article lays out an exact weight that you can expect to […]

  • Steve Shaw | Muscle and Brawn. Apr 18,2009 at 7:26 pm

    […] –Determining Natural Bodybuilding Potential […]

  • […] Determining Natural Bodybuilding Potential […]

  • Muscle and Brawn Mar 23,2009 at 8:26 pm

    Casey, I have changed some of the wording a bit in this article to leave it a tad bit more open ended. Thanks for your insight and inspiration.

  • Casey Butt Mar 7,2009 at 2:02 pm

    Hi Steve,

    I think that while these equations very well could be used to spot steroid users, they shouldn’t be the final word. After all, however UNLIKELY it is that someone naturally surpasses the predictions it would be very limiting and demoralizing to suspect every legitimate natural who does approach the predictions. In fact, that would probably guarantee that no competitor ever even tries to surpass them for fear of persecution …which would create a self-fulfilling prophecy.

    I think the equations should be applied to competitors and, based on the results, further blood tests, etc, could be applied afterward — though this would not detect drug users who haven’t yet reached even their natural potentials.

    I do, however, think equations of these forms should replace the BMI. Especially in medical fields where classifications of overweight, diet recommendations, drug dosages, etc are based on height and weight, but usually completely ignore the impact of bone structure. It’s a very simple adjustment to fit the lean body mass equation to the general untrained population for the sake of such things.

  • Steve Jan 17,2009 at 12:35 am

    No, they don’t use it as an indicator for natural competitions. But as a bystander, if someone is 10 pounds over their potential, you can pretty much know for sure that they have used something at some point.

    Nice looking website, btw.

  • No Nonsense Muscle Building Jan 16,2009 at 10:28 pm

    Hey this article was very interesting. I have often wondered if there was a way to tell potential. Do they use this in testing for natural vs. non natural bodybuilders?

    They person that came up with that sure has a brain to come up with that formula.

Leave Your Comment

Your Comment*

Your Name*
Your Webpage